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4x^2+115x-375=0
a = 4; b = 115; c = -375;
Δ = b2-4ac
Δ = 1152-4·4·(-375)
Δ = 19225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{19225}=\sqrt{25*769}=\sqrt{25}*\sqrt{769}=5\sqrt{769}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(115)-5\sqrt{769}}{2*4}=\frac{-115-5\sqrt{769}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(115)+5\sqrt{769}}{2*4}=\frac{-115+5\sqrt{769}}{8} $
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